image Transcription Text results Sets Of Masses Mass (9) 2 2009 1.96 Admission Essay Help

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Results Sets of Masses Mass (9) 2 2009 1.96 N Table 2.1. Assigned sets of masses and directions. ” Force Table Polygon Method Magnitude Magnitude (N)(N) … Show moreImage transcription text
Component Method sets of Masses Mass (9 ) Force (N ) Direction 200 g 1.96 N O’ , E 2 2009 1. 90 N 1710 , W 5009 4.90 270 , s -7 A : 1.96 N, O’E B : 1. 96 N, 1710 W C = 4. 90 N, 2700 S For the X- component of the resultant : RX = Ax Box ( x : [ 1.96 cos (o) 1.96 cos ( 171 ) 4.9 cos ( 270) ] N RX = 0. 02 N For the y- component of the resultant : Ry = Ayt By cy = [ 1. 96 sin (0) 1.96 sin ( 171 ) 4. 9 sin ( 270) ] N Ry = – 4.59 N Hence the resultant : R * 0. 02 N C – 4 . 59 N;… Show moreDoes your result using a graphical method for the magnitude and direction of the resultant agree with the analytical result to within two sigmas? If your result using a graphical method excludes the analytical result, identify and explain the possible sources of error. If your result is in agreement with the analytical method, explain the ways and precautions your group took into consideration to obtain a good result.