$6.2 The overall average on a process you are attempting to monitor is 50

Question: $6.2 The overall average on a process you are attempting to monitor is 50 units. The process standard deviation is 1.72. Determine the upper and lower control limits for a mean chart, if you choose to use a sample size of 5. P a) Set z = 3. b) Now set z = 2. How do the control limits change?Show transcribed image text 100% (2 ratings)Answer.:- Control limits are: mean /-(z*s.d/sqrt(n)) A.)50 /-(3*1.72/sqrt(5)) =50 /-2.308 =…View the full answerTranscribed image text: $6.2 The overall average on a process you are attempting to monitor is 50 units. The process standard deviation is 1.72. Determine the upper and lower control limits for a mean chart, if you choose to use a sample size of 5. P a) Set z = 3. b) Now set z = 2. How do the control limits change?